Fuel conversion.Β Reserved
Fuel conversion.Β Many different parameters was important for fuel conversion. The influence of fuel reactor temperature and specific fuel reactor inventory is shown in figure 6. Tests were performed using specific solids inventories between 619-1650 kg/MW. For the case with 1650 kg/MWth the fuel flow was not high enough to fluidize the bed and therefor nitrogen was added to the fuel to increase gas velocity. This of course, has the effect of diluting the methane stream, which could affect the reactivity. From the figure it is evident that the gas yield varied between 60-85%. The gas yield increased as a function of solids inventory and temperature. Another important parameter for fuel conversion was the total inventory of particles. Unfortunately the total inventory was impossible to keep constant due to the high elutriation of particles. The total inventory also affects the circulation of particles which is an important parameter for fuel conversion. In the current experiments the air flow was varied between 160-180 L/min, but no observable effect on conversion was seen.
Fuel conversion.Β The conversion of unburned gases inside the fuel reactor is defined as follows: ππΉπ
= 1 β ππ₯π¦πππ ππππππ, ππ’ππ πππππ‘ππ ππ₯βππ’π π‘ ππ₯π¦πππ ππππππ, ππ’ππ πππππ‘ππ ππππ ππΉπ
= 1 β πππππ ππππ€π (2 Β· πΆπ»4 + 0.5 Β· πΆπ + 0.5 Β· π»2 β π2)ππ’ππ πππππ‘ππ ππ₯βππ’π π‘ πππππ ππππ€π (2 Β· πΆπ»4 + 3.5 Β· πΆ2π»6 + 5 Β· πΆ3π»8 β π2)ππ’ππ πππππ‘ππ ππππ The different stoichiometric factors correspond to the oxygen demand of the respective gas compo- nent (see below). Oxygen itself gets a negative oxygen demand since it can be used to burn the other gases. The fuel conversion is an equivalent parameter to the methane conversion in other units. πΆπ»4 + π π2 π‘ͺ πΆπ2 + 2 π»2οΏ½οΏ½ πΆπ + π. π π2 π‘ͺ πΆπ2 π»2 + π. π π2 π‘ͺ π»2π πΆ2π»6 + π. π π2 π‘ͺ 2 πΆπ2 + 3 π»2π πΆ3π»8 + π π2 π‘ͺ 3 πΆπ2 + 4 π»2π Another important value is the global air-to-fuel ratio (Lambda). The available oxygen in the air reac- tor is set in relation to the needed oxygen for combustion of the corresponding amount of natural gas. The total available oxygen (air reactor feed) is lowered by the oxygen that is needed for combus- tion of added propane to the air reactor. π = (πΜπ2 )πππ πππππ‘ππ ππππ β (πΜπ2 )πππ πππππ‘ππ πππππ’π π‘πππ (πΜπ2 )πππ‘π’πππ πππ ππππππ