Treatment of results Sample Clauses

Treatment of results. If Procedure 1 or 2 were employed in making concentration measurements, use a linear regression analysis with Equation 4 under para- graph (a)(2)(v)(B) of this section to cal- culate kh at 25 °C for each pH employed in the hydrolysis experiments. Cal- culate the coefficient of determination (R2) for each rate constant. Use Equa- tion 3 under paragraph (a)(2)(v)(B) of this section to calculate the hydrolysis half-life using kh.
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Treatment of results. The molar absorption co- efficient e should be calculated for all absorbance maxima of the test sub- stance. The formula for this calcula- tion is: ε= A , c,i ×d where the quantities are as defined above (see Definitions and units).
Treatment of results. D a t a s h a ll be s u mm a r ized i n t a b u l a r fo r m .
Treatment of results. If P r oced ur e 1 o r 2 we r e e m plo y ed i n m a k i n g co n ce n t r a t io n m e a s ur e m e n t s, u se a li n e a r r eg r essio n a n a l y s i s wi t h E q u a t io n 4 un de r p a r a- g r a p h ( a)(2)(v)(B) of t h i s sec t io n t o c a l- c u l a t e kh a t 25 °C fo r e a c h p H e m plo y ed i n t h e hy d r ol y s i s expe r i m e n t s. Ca l- c u l a t e t h e coefficie n t of de t e r m i n a t io n ( R2) fo r e a c h r a t e co n s t a n t . Use E q u a- t io n 3 un de r p a r a g r a p h ( a)(2)(v)(B) of t h i s sec t io n t o c a lc u l a t e t h e hy d r ol y s i s h a lf- life u s i n g kh.
Treatment of results. T h e m ol a r a bso r p t io n co- efficie n t e s h o u ld be c a lc u l a t ed fo r a ll a bso r b a n ce m a xi m a of t h e t es t s u b- s t a n ce. T h e fo r m u l a fo r t h i s c a lc u l a- t io n i s: ε = A , c,i ×d w h e r e t h e q u a n t i t ies a r e a s defi n ed a bove ( see Defi n i t io n s a n d un i t s).
Treatment of results. ( i) T es t co m po un d (10 m g c a r - bo n) i s t h eo r e t ic a ll y co n ve r t ed t o 0.833 mm ol CO 2. Abso r bed CO2 p r ecipi t a t es a s B a CO3 f r o m B a(OH)2, c a u s i n g a r e- d u c t io n i n a l k a li n i t y b y t h e eq u iv a le n t of 16.67 m L of 0.1 N HCl fo r co m ple t e co n ve r s io n of t h e t es t co m po un d c a r - bo n t o CO2. T h e r efo r e, t h e pe r ce n t t h e- o r e t ic a l CO2 evolved f r o m t h e t es t co m - po un d i s c a lc u l a t ed a t a ny s a m pli n g t i m e f r o m t h e fo r m u l a : P e r ce n t CO2 evol u t io n =[( T F–C F )/16.67] 100 (fo r 10 m g/L t es t co m po un d c a r bo n) w h e r e: T F= m L 0.1 N HCl r eq u i r ed t o t i t r a t e B a(OH)2 s a m ples f r o m t h e t es t fl a s k C F= m L 0.1 N HCl r eq u i r ed t o t i t r a t e B a(OH)2 s a m ples f r o m t h e co n t r ol fl a s k . ( ii) T h e c u m u l a t ive pe r ce n t CO2 evo- l u t io n a t a ny s a m ple t i m e i s c a lc u l a t ed a s t h e s u mm a t io n of t h e pe r ce n t CO2 evolved a t a ll s a m ple poi n t s of t h e t es t . ( iii) T h e pe r ce n t DOC dis a ppe a r a n ce f r o m t h e t es t co m po un d i s c a lc u l a t ed f r o m t h e followi n g eq u a t io n: P e r ce n t DOC R e m ov a l=[1¥( D T Fx¥ DC Fx)/ ( D T Fo¥ DC Fo)] 100 w h e r e: D T F= Dissolved o r g a n ic c a r bo n f r o m t es t fl a s k DC F= Dissolved o r g a n ic c a r bo n f r o m co n t r ol fl a s k o= D a y ze r o m e a s ur e m e n t s x= D a y of m e a s ur e m e n t s d ur i n g t es t .
Treatment of results. (i) Test compound (10 mg car- bon) is theoretically converted to 0.833 mmol CO2. Absorbed CO2 precipitates as BaCO3 from Ba(OH)2, causing a re- duction in alkalinity by the equivalent of 16.67 mL of 0.1 N HCl for complete conversion of the test compound car- bon to CO2. Therefore, the percent the- oretical CO2 evolved from the test com- pound is calculated at any sampling time from the formula: Percent CO2 evolution=[(TF–CF)/16.67] 100 (for 10 mg/L test compound car- bon) where: TF= mL 0.1 N HCl required to titrate Ba(OH)2 samples from the test flask CF= mL 0.1 N HCl required to titrate Ba(OH)2 samples from the control flask.
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Treatment of results. (i) Test compound (10 mg car- where: DTF= Dissolved organic carbon from test flask DCF= Dissolved organic carbon from control flask o= Day zero measurements x= Day of measurements during test.
Treatment of results. The molar absorption co- efficient e should be calculated for all
Treatment of results. Test compound (10 mg car- bon) is theoretically converted to 0.833 mmol CO2.¥
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