Common use of Proof Clause in Contracts

Proof. If the height of α is 0, and the common frontier (α itself) exists, then α is common. If the height of α is σ, the children of α are all in common by using induction hypothesis with the height of the children at σ-1, then the vertex α is common. ■

Proof. If the height of α is 0, 0 and the common frontier (α itself) exists, then α is common. If the height of α is σ, the children of α are all in common by using following the induction hypothesis with the height of the children at being σ-1; then, then the vertex α is common. ■.

Proof. If the height of α is 0, 0 and the a common frontier (α itself) exists, then α is common. If the height of α is σ, the children of α are all in common by using induction hypothesis with the height of the children at σ-1, then the vertex α is common. ■.

Proof. If the height of α is 0, 0 and the common frontier (α itself) exists, then α is common. If the height of α is σ, the children of α are all in common by using an induction hypothesis with the height of the children at σ-1, then the vertex α is common. ■.

Proof. If the height of α is 0, and the common frontier (α itself) exists, then α is common. If the height of α is σθ, the children of α are all in common consistent by using virtue of the induction hypothesis with the height of the children at σ-1, then θ-1; the vertex α is then common. ■.

Proof. If the height of α is 0, 0 and the common frontier (α itself) exists, then α is common. If the height of α is σr, the children of α are all in common by using under the induction hypothesis with the height of the children at σ-1, then the vertex α is commonbeing r-1. ■⏹

Proof. If the height of α is 0, and the common frontier (α itself) exists, then α is common. If the height of α is σ, the children of α are all in common by using induction hypothesis with the height of the children at σ-1, then the vertex α is common. ■

Proof. If the height of α is 0, 0 and the common frontier (α itself) exists, and then α is common. If the height of α is σr, the children of α are all in common by using under the induction hypothesis with the height of the children at σ-1, then the vertex α is commonbeing r-1. ■

Proof. If the height of α is 0, 0 and the common frontier (α itself) exists, then α is common. If the height of α is σr, the children of α are all in common by using under the induction hypothesis with the height of the children at σ-1, then the vertex α is common. ■being r-1.

Proof. If the height of α is 0, 0 and the common frontier (α itself) exists, then α is common. If the height of α is σr, the children of α are all in common by using under the induction hypothesis with the height of the children at σ-1, then the vertex α is commonbeing r-1. ■

Proof. If the height of α is 0, and the common frontier (α itself) exists, then α is common. If the height of α is σr, plus the children of α are all in common by using the induction hypothesis with the height of the children at σ-1being r-1, then the vertex α is common. ■.