Game G3 definition

Game G3. We now furthermore reject any signed-authenticator that is non-oracle-generated whereas the player is still honest: the adversary does not know the signing key, and thus cannot correctly sign the authenticator. One can easily show that a di erence between G2 and G3 would lead to an attack against the one-time signature scheme.
Sample 1Sample 2
Game G3. This game is exactly same as the game G2 except that we use an instance (A = ga, B = gb) of CDH problem with its solution C = gab and the given values a, b in the simulation according to the following distribution of transcript, session key pair. ←− Z∗; k , . . . , k  ←− {0, 1}l  1 2 3  c1
Sample 1
Game G3. In this game, we abort the protocol runs if the adversary has been lucky in guessing the values k1 and k2 without asking the corresponding random oracle queries. We achieve this aim by adding more steps to processing the Send queries in the simulation. In processing the Send(Ci, ⟨µ, k1⟩) query, the client should check if ⟨2, C, S, m, µ, α, γ', k1⟩ ∈ LA or ⟨⟨C, m⟩, ⟨µ, k1⟩, ∗⟩ ∈ LP just before setting AcceptCi true (that is, right after checking that k1 = k1' ). If both tests fail, the client should terminate without accepting. In pro- cessing the Send(Sj, k2) query, the server should check if ⟨3, C, S, m, µ, β, γ', k2⟩ ∈ LA or ⟨⟨C, m⟩, ⟨µ, k1⟩, k2⟩ ∈ LP just before setting AcceptSj true (that is, right after checking that k2 = k2' ). If both tests fail, the server should terminate without accepting. This modification ensures that k1 and k2 will come, in valid form, from either the simulator that traces pairing or an adversary that has asked correct random oracle queries in all accepted cases. The two games G3 and G2 are perfectly indistinguishable unless the client rejects the valid k1 or the server rejects the valid k2. The rejection may happen only if the adversary has correctly guessed the values k1 and k2 without asking the corresponding random oracle queries. So we have: |Pr[Succ3] − Pr[Succ2]| ≤ O(qse)
Sample 1

Examples of Game G3 in a sentence

  • Since p | q, generating b from U (R5×1) instead of U (R5×1) makes the advantage of the adversary in Game G4−′at least as big as in game G3, as the adversary in Game G4 can easily calculate the same value for c as in Game G3.

  • Hence:G2G1G1|Pr[b ← A] − Pr[b ← A]| ≤ Pr[NOG-Com-OK] Game G3: In this game, we further straighten our requirements for openings in non-compromised terminals.

  • Since p | q, generating b from U (Rl×1) instead of U (Rl×1) makes the advantage of the adversary in Game G4−jat least as big as in game G3, as the adversary in Game G4 can easily calculate the same value for c as in Game G3.

  • Observe that, since the signatures computed by initiatorsand responders cannot be confounded, in Game G3 we neververify a message that was not signed by its unique partner.For the initiator we have that message log was signed by its partner and contains the responder’s nonce.

  • Game G3 is the same as game G2 except that we slightly modify the way the queries made by are answered; for this reason, we will use the fact that the guesses in game G2 were correct: the Test-ed session is built by the c0th operation and the corresponding broadcast has been sent by the i0th player.

  • In Game G3, we add a flag QUERY in line 09 and abort when it is raised.

  • Game G3: F generates a random session key for an interrupted session.

  • Let DK(Lµ, param, Hhk, hp, W) denotes an al- gorithm that can distinguish between Game G2 and Game G3 with advantageϵ.

  • The playgrounds are unusable and the kids-farm is having a hard time getting back to its original luster.

  • Game G3 and G4 are, thus, indistinguishable for the environment Z.( The real-world protocol AuCPace, thus emulates the ideal functionality FapwKE in therelaxed FpwKE, FRO , Ftunnel) or (FpwKE, FRO , Ftunnel) hybrid models.


More Definitions of Game G3

Game G3. In this game, if the adversary A can fake ⟨Sj, Fi, θ, ρ, Lj⟩ without making the random oracle queries, • Event E4: Similar to event E3, A is allowed to ask the Update(V a, UPW ) query. A can obtain updat- the scheme is simply terminated. This situation only appears in the Send queries. As a result, Games G3 and G2 are perfectly indistinguishable unless the vehicle rejects Sj or Lj, or the RA
Sample 1
Game G3. This game is exactly same as the game G2 except that we use an instance (A = ga, B = gb) of CDH problem with its solution C = gab and the given values a, b in the simulation according to the following distribution of transcript, session key pair. ←− Z∗; k , . . . , k  ←− {0, 1}l  1 2 3  c1 n q 1 n c2 x3 xn  oracle goes into an expecting state.  X1 = A , X2 = B , X3 = g , . . . , Xn = g ;  Similarly on Send1(Un, dn, Y1) and Send1(Un, dn, Yn−1)    = Epw
Sample 1
Game G3. This game considers a situation where A obtains the correct message transcript luckily without active participation of hash oracles H. The authentication phase of our protocol involves six messages communication mi, (i=1,..
Sample 1
Game G3. In this game, the attacker can, compared to the previous game, in addition execute Corrupt queries. As a result of the Corrupt(D) query, the attacker is able to extract dd and thus to retrieve K and perform the decryption in order to find Qu, Cd h rd, cd. However, as the attacker will not be able to find the response on the challenge, according to the predefined assumptions, it will not be able to find h and to derive a legitimate response to the user’s device or to construct the SK. When executing Corrupt(U, 1) query, the attacker has no access to the stored data and thus cannot derive useful information. Executing Corrupt(U, 2) will not lead to useful information unless the biometric data is correctly guessed, while in Corrupt(U, 3) the password should be guessed in order to be successful, following Equation 3. As a consequence: |Pr[succ3(A)] − Pr[succ2(A)]| ≤ legitimate entity, each one can conclude that the request is authenticated. As a consequence, impersonation and man-in-the-middle attacks become impossible. • Anonymity and untracebility: The identity related in- formation is encrypted in the message M1. Without knowledge of the private key material dd or z + du, C cannot be decrypted to derive the identity. For the same reasons, no guessing attacks allow to reveal the identity from M2. Also, the identity related information Qu on the device is stored encrypted. • Perfect forward secrecy: Suppose that βu, pwu are 3qs + C′qs′ , (6) leaked of the user’s device and access is obtained to
Sample 1
Game G3. The difference between G2 and G3 is that |Hash| |PUF| |D| where qh , qP , and qsend denote the number of hash, PUF, and Send queries, respectively. Also, Hash , PUF , and D denote the length of the hash output, length of the PUF-based output strings, and the length of the output of an algorithm that simulations of the Send and PUF queries are included in G3 . In the proposed scheme, we assume that the PUFs used in the UAVs are secure as defined in Section V-B. Therefore, as in G2 , we also have: AKE pAKE protocol, respectively. resolves a particular problem by running A on a simulation A,G2 A,G3 2|PUF| Adv − Adv ≤
Sample 1

Related to Game G3

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