E E Sample Clauses
E E. E Traininq�_�nd Health & Welfare Employer Contributions --·- XXX XXX XXX XXX XXX XXX XXX XXX TBD Fund Jurisdictional Assignment Plan ··--· --·-·--· Fund Drug & �-��-�hol Electrical Industry Bursary Fund '"' _....
E E. An employee who is on approved leave for reasons other than the suspended operations will not have their leave restored upon notice of suspended operations.
E E. CONTRACTOR shall employ a licensed certified public accountant, who will prepare and 32 file with ADMINISTRATOR, an annual, independent, organization-wide audit of related expenditures 33 during the term of this Agreement.
E E. Catering 1. 1. Catering for duty periods within a trip shall be provided as follows:
E E. Employee may, from time to time, submit to the Director of Personnel, for inclusion in personnel file, additional qualifications which acquired. The Employee, upon written request to the Director of may view the following documents from personnel file at a lime mutually convenient:
E E. E E E E Water Supply Man Knife Xxxxxxxxxx xxxxxxxxxxxxx Insulator Helper Tool Crib Attendant! Repairman: May May May U94 U96 months months months months months months E E E E E E E E
E E. [12] X. Xxxx, X. Xx-Xxxxxxxxxx, and X. Xxxx, “Incremental and decremental secret key agreement,” in Proc. IEEE Int. Symp. on Inf. Theory, July 2016, pp. 2514–2518. [13] X. Xxxxxxxxx, X. Xxxx, X. Xxxxxxx, and X. Xxxx, “Bounds on the communication rate needed to achieve SK capacity in the hypergraphical source model,” in Proc. IEEE Int. Symp. on Inf. Theory, July 2016, pp. 2504–2508. [14] X. Xxx, X. X. Xxxx, and X. Xxxxx´, “Common randomness and key generation with limited interaction,” CoRR, vol. abs/1601.00899, 2016. [15] X. Xxxxx, “Two-way source coding with a fidelity criterion,” IEEE Trans. Inf. Theory, vol. 31, pp. 735–740, Nov. 1985. [16] X. Xxxxxxxxxxx, X. Xx, X. Xxxx, X. Xxxxxxx, and X. Xxxxxx, “Secret key generation for a pairwise independent network model,” IEEE Trans. Inf. Theory, vol. 56, no. 12, pp. 6482–6489, Dec 2010. [17] X. Xxxxxxxxx, Combinatorial Optimization: Polyhedra and Efficiency. Springer, 2002. [18] I. Csisza´r and X. Xxxxxxx, “Secrecy capacities for multiterminal channel models,” IEEE Transactions on Information Theory, vol. 54, no. 6, pp. 2437–2452, June 2008.
E E. W E SAN SAN SAN SAN SAN SAN SAN SAN SAN SAN FO C C OEL OEL FO OEL C C X OEL OEL SAN SAN SAN SAN SAN SAN SAN SAN FO FO FO STM STM STM STM STM
E E. −(a + bζ3)ζiϕα, where i = 0 when [Q(α, ζ3) : Q(ζ3)] = 2 and i = 2 when [Q(α, ζ3) : Q(ζ3)] = 6. In other words, no non-zero element in Hom( d c)/5 is fixed by σ, and so (Hom( d c)/5)ΓQ = 0. (2.50) (b) Let c/d ∈ ⟨−33⟩ · Q×6, then c/d = (−3)3nδ6 for n = 0 or 1 and δ ∈ Q× as in part (b) of the proof of Lemma 2.5.3. Regardless of the value of n, we find that α = (√−3)nδ ∈ Q(ζ3). Hence, we get that G = Gal(Q(ζ3)/Q) = ⟨τ⟩, and the action of G on ϕα is (−1)nϕα. Moreover, since we are assuming that (a + bζ3)ϕα is fixed by τ , then b = 0 when n = 0, and b = 2a when n = 1, where in either case a is free. Hence, we have (Hom( d c)/5)ΓQ ∼= Z/5. (2.51) Proof of Theorem 2.5.2. This is a direct consequence of Lemmas 2.5.3 and